The areas of a ship’s
water plane are as follows:
Draft (m)
|
0
|
1
|
2
|
3
|
4
|
Area of WP (m2)
|
650
|
660
|
662
|
661
|
660
|
Code:
#include <iostream>
#define rho 1.025 //for salt water
using namespace std;
int main(){
float y0, y1, y2, y3, y4, simp, vol, ton, h;
cout << "Enter WP area values serially: <enter> ";
cin >> y0>> y1>> y2>> y3>> y4;
cout << "Enter draft: ";
cin >> h;
h /= 4;
simp = y0+(4*y1)+(2*y2)+(4*y3)+y4;
vol = (h*simp)/3;
ton = rho * vol;
cout << "The tonne displacement is " << ton;
}
Output:
Enter WP area values serially: <enter> 650
660
662
661
660
Enter draft: 4
The tonne displacement is 2705.32
Process returned 0 (0x0) execution time : 14.898 s
Press any key to continue.