Solution:
Given,
Breadth, B = 15 m
And, Depth, D = 10 m
Thickness of deck plate, tD = 5 mm = 0.005 m
Thickness of bottom and side plate, tB = tS = 9 mm = 0.009 m
Item |
Area (m2)
|
Lever (m) |
Moment (m3) |
Area x lever2
(m4) |
Iabout
own NA |
Deck Plating
(x1) |
0.075 |
9.9975 |
0.75 |
7.496 |
1.5627 x 10-7 |
Side Plating
(x2) |
0.18 |
5.002 |
0.9 |
4.50 |
1.494 |
Bottom Plating
(x1) |
0..135 |
0.0045 |
0.00061 |
2.73 x 10-6 |
9.1125 10-7 |
|
ΣA = 0.39 |
| ΣM = 1.651 |
Σ=12 |
Σ=1.5 |
So,
Distance of actual NA from assumed NA, `\overline y=\frac{1.651}{0.39}=4.23\;m`
So,
centroid of deck from NA is, `y_1=(10-4.23-0.0025)=5.7675m`
Centroid
of Keel from NA is, `y_2=4.23-0.0045=4.2255m`
`I_{O-O}=I_{own}+\sum_{Area\times Lever^2 } =1.5+12=13.5m^4`
`I_{NA}=I_{O-O}-A\overline y^2=13.5-0.39\times\left(4.23\right)^2=6.52m^4`
Applied Hogging moment, M = 65 MN-m
So,
Stress at deck = `\frac{My_1}{I_{NA}}=\frac{65\times5.7675}{6.52}=57.498MPa` In tension
So, Stress at bottom = `\frac{My_2}{I_{NA}}=\frac{65\times4.2255}{6.52}=42.12MPa` in Compression